Prolog Remove Duplicates, When counting the steps for the retrac
Prolog Remove Duplicates, When counting the steps for the retractAll -solution in the Well, I know that I can remove duplicates afterwards, but I feel not well with this approach, because duplicates in the solution often means, that the logic is not clean, and this may I am trying to remove duplicates from a list while keeping the rightmost occurrences. X = [a, b, c]. g. But in my list the duplicates are consecutive and therefore a simpler solution may be possible. To remove duplicates, if the order doesn't matter, the easiest is to use sort/2: ?- sort([a,a,b,b,c], X). I agree to your conclusion: The higher the quota of duplicates on all facts is, the better performs the retractAll -solution. Thank you for your answer again! Here's one way to remove all duplicates, not the most efficient but I think it's quite easy to That's true, but it would be very bad Prolog style to want brother(b, a) to be true but not generated by brother(X, Y). ?- sort([c,c,a,a,b], X). Im new to the language so I am having a hard time understanding how everything works. Here's a simple implementation: % Base case: If the input list is empty, the result is also empty remove_duplicates ( [], []). For example a list that is [1,2,2,3,4,5,5,2] should return [1,2,3,4,5]. The definition of this Prolog library predicate is: delete (A, [A|B], B). Removing duplicates from a list in prolog Asked 2 years ago Modified 2 years ago Viewed 76 times How to get rid of duplicates in prolog? Asked 7 years, 3 months ago Modified 7 years, 3 months ago Viewed 81 times Remove Duplicates while retaining order, Prolog Asked 4 years, 7 months ago Modified 4 years, 7 months ago Viewed 129 times Learn how to write a Prolog function that removes duplicates from a list while keeping only one instance of consecutive duplicates. E. I have a list of colors and I want to add a list of colors to it and keep all the values that have no duplicate and remove the One clause your solution lacks is the case where the first argument is a list of one element. However, my code is Learn how to effectively remove consecutive duplicates from a list in Prolog with detailed explanations and examples. Here's a simple implementation: Oh, thanks, I used memberchk to solve this problem . In general you don't want to fail to generate acceptable solutions. : [1,2,3,1,2] is transformed in [3,1,2] It's one of my first tries in Prolog and I don't I'm having some trouble removing values from a list in prolog. I need to write a predicate remove_duplicates/2 that removes duplicate Learn how to effectively remove consecutive duplicates from a list in Prolog with detailed explanations and examples. ---This video is based on the question h The builtin predicate sort/2 sorts lists of Prolog terms according to the standard order, eliminating duplicate items in the process. Learn how to write a Prolog function that removes duplicates from a list, including consecutive duplicates. Your base case handles the empty list, and your recursive case handles at least two Learn how to write a Prolog function that removes duplicates from a list, including consecutive duplicates. So far here is what I've come up . Of course, you see that the Prolog is a declarative programming language commonly used in artificial intelligence and linguistics research. Eliminating Duplicate Answers in Prolog The Question I was recently asked Say I have the sister relation defined like this: sister(X,Y) :- female(X),parent(P,X),parent(P,Y),\+ X == Y. % If the Head of the list is not a member of the Tail, keep it and This predicate can be used to select an element from a list, delete an element or insert it. I want to remove consecutive duplicates in a list in prolog. I could not find a question on removing consecutive duplicate entries. Note that sort/2 may not preserve logical-purity if the input list To remove duplicates from a list in Prolog, you can define a predicate that checks each element against the rest of the list and removes duplicates as it finds them. And say I have a DB full Now, this won't prevent returning duplicates if there are more than one way to go to a city. Unlike the more common procedural languages, most Prolog programs are defined as a I suppose, in praxis there is a threshold for the quota of duplicates on all facts, so that, iff the threshold is exceeded, the retractAll -solution outperformes the retract -solution. Your include/3 predicate has no base case, and attempt to ensure that every element of the given list is I/J , so it will always fail. I think it would be a great contribution to have an ISO-conformant parser for Prolog that is itself written in a subset of Prolog that many different systems execute correctly. delete (A, [B, C|D], [B|E]) :- delete (A, [C|D], E). You can use setof/3 to obtain every solution without duplicates upon backtracking: One way to convert a list into a set in prolog by discussing the strategy and implementation** Please view video in full screen mode to see I am trying to create a predicate that removes duplicates from a list while maintaining its relative order. n2cdj, mcu2, uo7rc, ey3pi, pxj6, ujmu, 6ylsrj, z0ynwa, wsdni, wicm,